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-0.0003x^2+0.06x+3.75=0
a = -0.0003; b = 0.06; c = +3.75;
Δ = b2-4ac
Δ = 0.062-4·(-0.0003)·3.75
Δ = 0.0081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.06)-\sqrt{0.0081}}{2*-0.0003}=\frac{-0.06-\sqrt{0.0081}}{-0.0006} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.06)+\sqrt{0.0081}}{2*-0.0003}=\frac{-0.06+\sqrt{0.0081}}{-0.0006} $
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